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RC High-Pass Filter Calculator

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First-order passive RC high-pass: get the cut-off from R/C or back out the components from a target f_c, with attenuation and phase at a probe frequency.

Key points

RC High-Pass Filter Calculator: First-order passive RC high-pass: get the cut-off from R/C or back out the components from a target f_c, with attenuation and phase at a probe frequency. Formula: f_c = 1/(2πRC) | |H| = (f/f_c)/√(1+(f/f_c)²). Enter parameters on the DD-CAT IDE online tool page to get results instantly, with a calculation-model diagram that updates with the inputs. A passive first-order high-pass rises 20dB per decade and attenuates the passband by R/(R+1/ωC); the next stage must have an input impedance well above R. The output is across R; taken across C it becomes a low-pass.

Inputs

f_c = 1/(2πRC) | |H| = (f/f_c)/√(1+(f/f_c)²)

Calculation model (updates with parameters)

VinCRVoutf_c = 1.592 kHzτ = 100 µs

Bode plot (magnitude / phase, updates with parameters)

High-pass gain |H|-50-40-30-20-1000°45°90°100 Hz1 kHz10 kHz100 kHzf (log axis)dBphase1.592 kHz-3.0 dB+45°1 kHz · -5.5 dB
Cut-off f_c1.592 kHz
Resistor R1 kΩ
Capacitor C100 nF
Time constant τ100 µs
观察频点 1 kHz 的衰减-5.48 dB(0.5320×)
Phase at that frequency57.9°
Rise time (10–90%)220 µs

Engineering notes

  • A passive first-order high-pass rises 20dB per decade and attenuates the passband by R/(R+1/ωC); the next stage must have an input impedance well above R.
  • The output is across R; taken across C it becomes a low-pass.

FAQ

What is RC High-Pass Filter Calculator for?
First-order passive RC high-pass: get the cut-off from R/C or back out the components from a target f_c, with attenuation and phase at a probe frequency.
What is the formula for RC High-Pass Filter Calculator?
Core formula: f_c = 1/(2πRC) | |H| = (f/f_c)/√(1+(f/f_c)²). The tool returns results instantly using this formula and the selected parameters.
What engineering notes should I keep in mind when using RC High-Pass Filter Calculator?
A passive first-order high-pass rises 20dB per decade and attenuates the passband by R/(R+1/ωC); the next stage must have an input impedance well above R. The output is across R; taken across C it becomes a low-pass.