Specific Heat Calculator (Q=mcΔT)
Compute the heat absorbed or released when an object heats or cools via Q = m·c·ΔT, with results in joules / kilojoules / kilocalories and common material specific-heat references.
Key points
Specific Heat Calculator (Q=mcΔT): Compute the heat absorbed or released when an object heats or cools via Q = m·c·ΔT, with results in joules / kilojoules / kilocalories and common material specific-heat references. Formula: Q = m·c·ΔT. Enter parameters on the DD-CAT IDE online tool page to get results instantly, with a calculation-model diagram that updates with the inputs. Q = m·c·ΔT: heat = mass × specific heat × temperature change; positive for heat absorption, negative for release. Specific heat is a material property: water 4186, copper 385, aluminum 900, iron/steel ≈ 450, air (constant pressure) ≈ 1005 J/(kg·K).
Inputs
Q = m·c·ΔTCalculation model (updates with parameters)
| Heat Q | 334.9 kJ | Q = m·c·ΔT (positive absorbs heat, negative releases heat) |
| Heat (kilojoules) | 335kJ | |
| Heat (kilocalories) | 80kcal | 1 kcal = 4186.8 J |
| Temperature change ΔT | 80K | Δ1 K = Δ1 °C |
| Heating time (at 1 kW) | 335s | Ignoring heat loss, estimated at 1 kW power |
Engineering notes
- Q = m·c·ΔT: heat = mass × specific heat × temperature change; positive for heat absorption, negative for release.
- Specific heat is a material property: water 4186, copper 385, aluminum 900, iron/steel ≈ 450, air (constant pressure) ≈ 1005 J/(kg·K).
- 1 kcal (kilocalorie) = 4186.8 J, the heat needed to raise 1 kg of water by 1 °C.
FAQ
- What is Specific Heat Calculator (Q=mcΔT) for?
- Compute the heat absorbed or released when an object heats or cools via Q = m·c·ΔT, with results in joules / kilojoules / kilocalories and common material specific-heat references.
- What is the formula for Specific Heat Calculator (Q=mcΔT)?
- Core formula: Q = m·c·ΔT. The tool returns results instantly using this formula and the selected parameters.
- What engineering notes should I keep in mind when using Specific Heat Calculator (Q=mcΔT)?
- Q = m·c·ΔT: heat = mass × specific heat × temperature change; positive for heat absorption, negative for release. Specific heat is a material property: water 4186, copper 385, aluminum 900, iron/steel ≈ 450, air (constant pressure) ≈ 1005 J/(kg·K). 1 kcal (kilocalorie) = 4186.8 J, the heat needed to raise 1 kg of water by 1 °C.