Linear Thermal Expansion Calculator (ΔL=αL₀ΔT)
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Compute linear expansion ΔL = α·L₀·ΔT and the expanded length for pipes, structures and precision parts.
Key points
Linear Thermal Expansion Calculator (ΔL=αL₀ΔT): Compute linear expansion ΔL = α·L₀·ΔT and the expanded length for pipes, structures and precision parts. Formula: ΔL = α·L₀·ΔT. Enter parameters on the DD-CAT IDE online tool page to get results instantly, with a calculation-model diagram that updates with the inputs. Linear expansion ΔL = α·L₀·ΔT: α is the coefficient of linear expansion in 1/°C; most metals have α on the order of 10⁻⁵. Common α (×10⁻⁶/°C): copper 17, aluminum 23, steel ≈ 12, glass ≈ 9, concrete ≈ 10.
Inputs
ΔL = α·L₀·ΔTCalculation model (updates with parameters)
| Linear expansion ΔL | 0.00136m | ΔL = α·L₀·ΔT |
| Expanded length L | 1m | L = L₀ + ΔL |
| Temperature change ΔT | 80K | |
| Expansion per meter | 1360µm/m | Relative expansion α·ΔT |
Engineering notes
- Linear expansion ΔL = α·L₀·ΔT: α is the coefficient of linear expansion in 1/°C; most metals have α on the order of 10⁻⁵.
- Common α (×10⁻⁶/°C): copper 17, aluminum 23, steel ≈ 12, glass ≈ 9, concrete ≈ 10.
- Long pipes / rails / bridges need expansion joints; otherwise tens of degrees of temperature change produce significant deformation and thermal stress.
FAQ
- What is Linear Thermal Expansion Calculator (ΔL=αL₀ΔT) for?
- Compute linear expansion ΔL = α·L₀·ΔT and the expanded length for pipes, structures and precision parts.
- What is the formula for Linear Thermal Expansion Calculator (ΔL=αL₀ΔT)?
- Core formula: ΔL = α·L₀·ΔT. The tool returns results instantly using this formula and the selected parameters.
- What engineering notes should I keep in mind when using Linear Thermal Expansion Calculator (ΔL=αL₀ΔT)?
- Linear expansion ΔL = α·L₀·ΔT: α is the coefficient of linear expansion in 1/°C; most metals have α on the order of 10⁻⁵. Common α (×10⁻⁶/°C): copper 17, aluminum 23, steel ≈ 12, glass ≈ 9, concrete ≈ 10. Long pipes / rails / bridges need expansion joints; otherwise tens of degrees of temperature change produce significant deformation and thermal stress.
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