What is the formula for Latent Heat Calculator (Q=mL)?

Core formula: Q = m·L. The tool returns results instantly using this formula and the selected parameters.

Latent Heat Calculator (Q=mL)

Compute the heat absorbed or released during a phase change (melting / freezing / vaporization / condensation) via Q = m·L.

Key points

Latent Heat Calculator (Q=mL): Compute the heat absorbed or released during a phase change (melting / freezing / vaporization / condensation) via Q = m·L. Formula: Q = m·L. Enter parameters on the DD-CAT IDE online tool page to get results instantly, with a calculation-model diagram that updates with the inputs. During a phase change the temperature stays constant; the heat absorbed/released equals mass × latent heat (Q = mL). Water fusion heat ≈ 334 kJ/kg and vaporization heat ≈ 2260 kJ/kg (100 °C, atmospheric pressure).

Inputs

Q = m·L

Calculation model (updates with parameters)

Latent heat Q	334 kJ	Q = m·L
Heat (kilojoules)	334kJ
Heat (kilocalories)	79.8kcal
Equivalent evaporated water mass	0.148kg	Converted using water vaporization heat 2260 kJ/kg

Engineering notes

During a phase change the temperature stays constant; the heat absorbed/released equals mass × latent heat (Q = mL).
Water fusion heat ≈ 334 kJ/kg and vaporization heat ≈ 2260 kJ/kg (100 °C, atmospheric pressure).
Evaporative cooling is an important mechanism for body and equipment cooling: evaporating 1 kg of water removes about 2260 kJ.

FAQ

What is Latent Heat Calculator (Q=mL) for?: Compute the heat absorbed or released during a phase change (melting / freezing / vaporization / condensation) via Q = m·L.
What is the formula for Latent Heat Calculator (Q=mL)?: Core formula: Q = m·L. The tool returns results instantly using this formula and the selected parameters.
What engineering notes should I keep in mind when using Latent Heat Calculator (Q=mL)?: During a phase change the temperature stays constant; the heat absorbed/released equals mass × latent heat (Q = mL). Water fusion heat ≈ 334 kJ/kg and vaporization heat ≈ 2260 kJ/kg (100 °C, atmospheric pressure). Evaporative cooling is an important mechanism for body and equipment cooling: evaporating 1 kg of water removes about 2260 kJ.